6x^2-20x-4000=0

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Solution for 6x^2-20x-4000=0 equation:



6x^2-20x-4000=0
a = 6; b = -20; c = -4000;
Δ = b2-4ac
Δ = -202-4·6·(-4000)
Δ = 96400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{96400}=\sqrt{400*241}=\sqrt{400}*\sqrt{241}=20\sqrt{241}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-20)-20\sqrt{241}}{2*6}=\frac{20-20\sqrt{241}}{12} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-20)+20\sqrt{241}}{2*6}=\frac{20+20\sqrt{241}}{12} $

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